Originally posted by: Selena1

Hello,

My problem is big and I know it will take hours to run it to optimality. I want to set a maximum running time to 2 hours. How can I do it in ilog cplex optimization studio?

Regards,
Selena
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Originally posted by: SystemAdmin

Hi
Did you try TiLim parameter in cplex solver?
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Originally posted by: liguo66

hi

how to use tilim.

i use it like this before minimize. appears 2 errors.（they are Chinese characters and not displayed properly)

execute{
        cplex.tilim = 120;
}

my code is simple :

/*********************************************
 * OPL 12.7.0.0 Model
 *********************************************/
using CP;

int nbJobs = ...;
int nbMchs = ...;

range Jobs = 0..nbJobs-1;
range Mchs = 0..nbMchs-1;

int OpDurations[j in Jobs][m in Mchs] = ...;

dvar interval itvs[j in Jobs][m in Mchs] size OpDurations[j][m];
dvar sequence mchs[m in Mchs] in all(j in Jobs) itvs[j][m];

execute{
        cplex.tilim = 120;
}

minimize sum(j in Jobs) endOf(itvs[j][nbMchs-1]);
subject to {
  forall (j in Jobs, o in 0..nbMchs-2)
    endBeforeStart(itvs[j][o], itvs[j][o+1]);
  forall (m in Mchs)
    noOverlap(mchs[m]);
  forall (m in Mchs:0<m)
    sameSequence(mchs[0], mchs[m]);
   
}

execute {
  for (var j = 0; j <= nbJobs-1; j++) {
    for (var o = 0; o <= nbMchs-1; o++) {
      write(itvs[j][o].start + " ");
    }
    writeln("");
  }
}:

 

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Hi

with CPo you d rather write

execute{
        cp.param.timelimit= 120;
}

regards

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Originally posted by: liguo66

it works thanks very munch!

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Originally posted by: sandeepsinghchauhan

Hello Alex,

According to your suggestion for execution time limit

execute{
            cp.param.timelimit= 120;
    }

I have also put the same in my model. But my model stop 00:02:09:38. But I think it should be stop at 00:02:00:00? Please help me to calrify this doubt

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Hi,

can you try with oplrun ?

the timelimit is for the search and does not include OPL part, this could explain.

regards

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