Originally posted by: Marko_Obert

Hi,

 

I want to create a range with a step, similar to e.g. numpy.arange (https://docs.scipy.org/doc/numpy/reference/generated/numpy.arange.html)

start = 1

stop = 3

step = 0.5

to obtain a range of: 1.0, 1.5, 2.0, 2.5

 

According to the documention https://www.ibm.com/support/knowledgecenter/en/SSSA5P_12.5.1/ilog.odms.ide.help/OPL_Studio/opllang_quickref/topics/tlr_opl_range.html it is possible to define a range of type "float"

"range float 1.0 ... 2.0 "but I can not find a paramter to define the step.

 

If this is not possible, I would like to try an alternative solution, but I'm also not sure how to achieve it.

 

in common.mod I create an hours tuple:

 

{float} Hours= ...;    ## [1, 1.5, 2.0, 2.5.... 8759.5, 8760] 

 

Is it somehow possible to "slice" an subset of this tuple

start = 4000

stop = 4002

e.g. subset = Hours[start:stop] ? => subset = [4000.0, 4000.5, 4001.5]

 

Kind regards,

Marko

 

 

 

 

#CPLEXOptimizers
#DecisionOptimization

Instead of a "range with step" you can use a set:

int start = 1;
int stop = 3;
float step = 0.5;
{float} values = { start + i * step | i in 0..ftoi(ceil((stop - start) / step)) };

As for array slicing, a set should do as well:

{float} hours = { 1., 2., 3., 4., 5., 6., 7., 8. };
int sstart = 2;
int send = 3;
{float} subset = { item(hours, i) | i in sstart..send };

 

#CPLEXOptimizers
#DecisionOptimization

Originally posted by: Marko_Obert

Nice, thank you :-)

#CPLEXOptimizers
#DecisionOptimization