Originally posted by: sandeepsinghchauhan

A= [10 20 30 40];

B = [1000 2000 3000 4000];

C = [ -1000 -2000 -3000 -4000];

How can i make

Bound = [10 1000 -1000 20 2000 -2000 30 3000 -3000 40 4000 -4000];

please help

Hi,

range r=1..4;
 
int A[r]= [10,20, 30, 40];

int B[r] = [1000 ,2000 ,3000 ,4000];

int C[r] = [ -1000, -2000 ,-3000 ,-4000];

 

int values[i in 1..3][j in r]=(i==1)?A[j]:((i==2)?B[j]:C[j]);
int Bound[i in 1..12]=values[(i-1) mod 3+1][(i-1) div 3+1];

execute
{

writeln(Bound);
}

gives

 [10 1000 -1000 20 2000 -2000 30 3000 -3000 40 4000 -4000]

regards

Originally posted by: sandeepsinghchauhan

Thanks for your help

If i want to go in reverse like if i have Bound =  [10 1000 -1000 20 2000 -2000 30 3000 -3000 40 4000 -4000]

and i want to create A = [10,20, 30, 40]; B= [1000 ,2000 ,3000 ,4000]; C = [ -1000, -2000 ,-3000 ,-4000]

how can i do it

please help

Hi

int Bound[1..12]=[10, 1000, -1000, 20, 2000, -2000, 30 ,3000, -3000, 40, 4000 ,-4000];

range r=1..4;
     
int values[1..3][r]=[ ((i-1) mod 3)+1 : [ (i-1) div 3+1 : Bound[i] ] | i in 1..12 ];

int A[i in r]=values[1][i];
int B[i in r]=values[2][i];
int C[i in r]=values[3][i];
 
execute
{
  writeln(A,B,C);
}

gives

[10 20 30 40] [1000 2000 3000 4000] [-1000 -2000 -3000 -4000]

But I wonder why you want to turn A,B,C into Bounds and then back again into A,B,C

regards