Originally posted by: SystemAdmin

[zhzhang said:]

How to declare a 4D array in concert?
My code is:
IloArray<IloNumVarArray<IloNumVarArray<IloNumVarArray> > > IloNumVarArray4;

is it right?


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Originally posted by: SystemAdmin

[TheEngineer said:]

That code is pretty much unreadable for other people and I guess it will not be working.

For my 3d arrays I use the following snippet:

typedef IloArray<IloNumVarArray> NumVarMatrix;
typedef IloArray<NumVarMatrix> NumVarMatrix3d;

To extend it to 4 dimensions you could use (I did not test it yet):
typedef IloArray<NumVarMaxtrix3d> NumVarMatrix4d;


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Originally posted by: lriWANGCHEN

I also want to define a 4d array like y[i][j][s][t] by C++, and the element in the array is 0<=y<=1.

As you said, I can define the typedef, but how can I give the define the range of the array? I just do it like this, but then?

NumVarMatrix4d Y(env,n);
for(int i=0;i<n;i++)
{
Y[i]=NumVarMatrix(env,n);
}

Thank you.
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Originally posted by: lriWANGCHEN

as the question above, if I define it like this ,is it right?

NumVarMatrix4d Y(env,n);
for(int i=0;i<n;i++)
{
Y[i]=NumVarMatrix(env,n);
for(int j=0;j<n;j++)
{
Y[i][j]=IloNumVarArray(env,n,0.0,1.0,ILOFLOAT);
}
}

Thank you very much.
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Originally posted by: SystemAdmin

As far I can see you initialize only 3 dimensions. Something like this could work:

NumVarMatrix4d Y(env,n);
for(int i=0;i<n;i++)
{
   Y[i]=NumVarMatrix3d(env,n);
   for(int j=0;j<n;j++)
   {
      Y[i][j] = NumVarMatrix(env, n);
      for (int k = 0; k < n; ++k)
         Y[i][j][k]=IloNumVarArray(env,n,0.0,1.0,ILOFLOAT);
   }
}

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Originally posted by: SystemAdmin

You cannot specify the length of the arrays in the typedef. The length of the arrays is a runtime property.
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