Originally posted by: Dortmunder

Hi everyone,

I have a beginners question about for loops in CPLEX.

For my program I need to check at which time step my binary matrix has the last "1" for each unit and use it on one of my constraints.

If I write my code in CPLEX according to the help documentation it should look like this (NbTimeSteps is the TimeSteps arrays range):

forall (u in Units)

 for (t in TimeSteps == NbTimeSteps; t>1; t--)

  { if (BinaryMatrix[u][t] == 1)

     ( Matrix[u][t] == Array[u] break ) }

Apparently the syntax is very different and I figured that at least the for-loop should look more like this:

     for (t in TimeSteps == NbTimeSteps, t>=2, t-1)

Still, the if-condition cannot be operated in the for-loop. Is it a generally disallowed operation or is my syntax simply wrong?

Would the break operator work if my if-condition worked?

Grateful for any help I can get! Thanks in advance!

Hi

first you can write outside of the subject to block

int lastelement[i in 1..scale]=max(j in 1..scale : b[j]==1) j;

and then in the constraint block something like

forall(i in 1..scale) x[i][lastelement[i]]==2;

regards

Originally posted by: Dortmunder

Hi Alex,

thanks a lot for your help, it works!

Btw you probably meant b[i][j] == 1, right? ;-)

Thanks again

Tarik

Hi

indeed, I meant b[i][j] == 1

regards