Originally posted by: CPlex_NooBie

Greetings!

I am working on a problem where I need a variable size matrix. For example Row 1 might have 3 Columns, Row 2 has 5 Columns and Row 3 has 6 columns. So I created a matrix of 3x6 since the max length is 6 and using the required lengths. But is there a way to create a dynamic array? 
Thanks.

Hi,

you could use a tuple set instead.

tuple t

{

  int column;

  int row;

  int value;

};

and then you do not have to book more memory than what you need and you may grow your array.

regards

Originally posted by: Anatu

hi

i have a similar problem so im joining your conversation, thanks 

how do i initialize such a tuple set? since a tuple set cannot be initialized with a range?

lets say i already have an array of the lengths:

  int rows [nb in nbOfColumns];

after i declare the tuple like you suggested, how do i continue so that the tupleset will contain the row, the column index and the value for each index?

thank you

Hi,

let me add a small example:

range nbOfColumns=1..4;

int rows [nb in nbOfColumns]=nb;

tuple t
{
      int column;
      int row;
      int value;
    };
    
    
{t} s={<col,row,row*col> | col in nbOfColumns,row in 1..rows[col] };   

execute
{
writeln(s);
}

which gives

 {<1 1 1> <2 1 2> <2 2 4> <3 1 3> <3 2 6> <3 3 9> <4 1 4>
     <4 2 8> <4 3 12> <4 4 16>}

regards