Originally posted by: SystemAdmin
Hi,
Kindly respond to my previous post in this thread. I need your help to understand...
However I have pasted the same post here below,
When I give the command
mipopt it generates a output. In the table
ItCnt column represents the count. And also it gives several feasible solution until a optimal objective is achieved. So in my example shown below, 1002 iterations are performed for the optimal objective solution.
How does this 1002 iterations perform?
Does 1 iteration refers to a complete loop of all constraints?
Can I track how iterations are performed under each constraints while it is solving the problem?
How to display or write other solutions? since in my example shown, there are 4 solutions found. I need to display and write other solutions too for comparison with my optimal solution.
Nodes Cuts/
Node Left Objective IInf Best Integer Best Bound ItCnt Gap
0+ 0 0.0000 92 ---
0 0 2071.3152 11 0.0000 2071.3152 92 ---
0+ 0 978.0000 2071.3152 92 111.79%
0 0 1770.2542 11 978.0000 Cuts: 102 279 81.01%
0 0 1730.1735 11 978.0000 Cuts: 111 476 76.91%
0+ 0 1013.0000 1730.1735 476 70.80%
0 0 1707.0642 11 1013.0000 Cuts: 99 622 68.52%
0 0 1692.1570 11 1013.0000 Cuts: 93 728 67.04%
0 0 1690.3150 11 1013.0000 Cuts: 55 836 66.86%
0 0 1686.8129 11 1013.0000 Cuts: 38 930 66.52%
0 0 1686.0921 11 1013.0000 Cuts: 38 976 66.45%
0 0 1684.7987 11 1013.0000 Impl Bds: 18 997 66.32%
0 0 1684.7092 11 1013.0000 Impl Bds: 2 1000 66.31%
0 0 1684.7092 11 1013.0000 Impl Bds: 2 1002 66.31%
0+ 0 1048.0000 1684.7092 1002 60.75%
0 0 cutoff 1048.0000 1048.0000 1002 0.00%
Elapsed real time = 0.33 sec. (tree size = 0.00 MB, solutions = 4)
Thanks
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