Hello, I'm looking for a UPS for some equipment, including an ibm storage FS5015, but I can't find the value in KVA and it only shows it in WATTS, could you help me find it? Since I don't see the power factor anywhere, I send the data that I found in its electrical specification, thanks.

Electrical power
• AC power:
– Voltage range: 100 - 240 V AC
– Frequency: 50 - 60 Hz
– Power: 800 watts
• DC power:
– Voltage range: -42 to -60 V DC
– Voltage nominal: -48 V DC
– Current: 12.0 A
– Power: 800 watts
Models with the DC power feature require an electrically rated 20A circuit breaker for
the -48 V DC input. The wiring between the DC power source and the FlashSystem
5000 DC power supply connectors must be with 12 AWG copper wires.

Miguel,

1 kVA = 1,000 W

So, the above system requires 0.8kVA.

Hello Miguel,

this depends on the actual configuration. If it's just a controller enclosure including the drives, the 0.8kVA will fit. If expansion units are added, this must of course be taken into account, including those planned for the future. Additionally you have to consider the necessary runtime when determining the size of a UPS. So how long do the hosts that use the storage and the associated infrastructure need power such as: Ethernet & SAN Switches. These should also be powered by the same or another UPS.

Best Regards

Dear Miguel,

mainly all PowerSupplys in the IT build after 1996 have a powerfactor correction built in, so you can calculate 1 = 1. On the other hand there is a USV Selector on the website of APC (APC-USV-Selektor/-Rechner: Finden Sie das passende USV-System) that may help finding the right USV for the System.
As a rule of thumb the device behind the USV should not exeed 60% load, so you should use a USV with around 1500 kVA (related to full 800W)

As Patrick mentioned before, the needed Power depends on the configuration and can be estimated with the IBM STORM (Storage Modeller).
If you dont have access to the modeller, i am able to give you the numbers.

kind regards
Martin