Decision Optimization

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Need help in understanding OPL syntax

  • 1.  Need help in understanding OPL syntax

    Posted Mon July 27, 2020 11:21 AM
    The OPL documentation at the location 
    IDE and OPL > Optimization Programming Language (OPL) > Language User's Manual > Introduction to OPL > A short tour of OPL > Constraint programming: an inventory matching problem
    describes a solution to an inventory problem called 'steelmill'.

    The solution to the problem expresses the constraint that a slab can be used to make coils of at most two colours as 
    forall(s in 1..nbSlabs) colorCt: sum (c in 1..nbColors) (or(o in 1..nbOrders : colors[o] == c) (where[o] == s)) <= 2;
    
    I am finding it hard to understand this syntax, especially the portion (or(o in 1..nbOrders : colors[o] == c) (where[o] == s))
    The or function, I thought, returns 1 if the order has colour 'c'. The portion(where[o] == s)selects an order that is used the slab b.  But what does the juxtaposition of the two predicates mean?


    <main role="main">
    </main>

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    Amey Joshi
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    #DecisionOptimization


  • 2.  RE: Need help in understanding OPL syntax

    Posted Mon July 27, 2020 11:41 AM
    The term o in 1..nbOrders : colors[o] == c yields all the orders that have color c. So or(...) iterates over all orders that have color c. For each of these orders o it checks whether where[o] == s. It finally forms the logical OR of all these tests. So the whole OR evaluates to true if there is at least one order of color c that has where equal to s.

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    Daniel Junglas
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