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 Automation script for opening an application and pop-up a dialog

Levente Warta's profile image
Levente Warta posted Wed October 15, 2025 09:44 AM

Hi!

What is the correct way to open a record from an automation script and immediately display a pop-up dialog? (It has an action launch point.)

First, I tried this:

wcs = service.webclientsession()
app = wcs.getCurrentApp()
appBean = app.getAppBean()
# wo is the record I want to open:
uID = wo.getUniqueIDValue() 
#Jump to the record:
appBean.moveToUniqueId(uID)
#I'm not sure these 2 lines are needed:
appBean.setupBean(wcs)
appBean.save()

#open the dialog:
event = WebClientEvent("DIALOG_ID", app.getId(), None, SessionContext(wcs))
wcs.queueEvent(event)

This code works with the UI. 

The problem with the above code is that the ResultsBean remains the same in the background (i.e. not the new record that I jumped to), which can cause a lot of bugs. 

 I tried also something like this:

wcs = service.webclientsession()
app= wcs.getCurrentApp()
appBean = app.getAppBean()
uID = lastNRC.getUniqueIDValue()
    
changeAppEvent = WebClientEvent("changeapp", app.getId(), "ace_wo_base", None, None, None, uID, wcs);
wcs.queueEvent(changeAppEvent)
    
openDialogEvent = WebClientEvent("ACE_MATERIAL_REQ", app.getId(), None, SessionContext(wcs))
wcs.queueEvent(openDialogEvent )

With this code the ResultsBean changes as expected, but the dialog does not pop-up.

Do you have any idea how could I achieve this?