Originally posted by: SGLFORUM

How to pass the output of a script as the input of another script?
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Originally posted by: bhead

Without knowing what the ouput looks like and what the second script expects I can only guess. In a new script capture the output in a variable.

OutPut=$(/mydirectory/myscript1.ksh)

/mydirectory/second_script.ksh $OutPut

Not sure if that'll work or not.

Edit

Those are displaying as being on one line, should be 2 lines.

Message was edited by: bhead
#AIX-Forum

Originally posted by: nagger

Your question is very vague.
If you mean within one script, how do I run a further script but get the data back in the first script then try something like this example.

In a shell script you can use:

cat /etc/passwd | while read i
do
echo the output was $i
done

Replace "cat /etc/passwd" with your script.
the $i shell variable will be the lines of output from the command or sub script.

If the second script returns just one line

date | read j
echo Data returned was $j

or

k=`date`
echo variable k contains $k

This actually works with multiple lines but its hard to extract just some of the data.

Hope this helps, N
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Originally posted by: SGLFORUM

> SGLFORUM wrote:
> How to pass the output of a script as the input of another script?
Let me explain in detail.

I have two script, say "a.sh" & "b.sh". I am calling "a.sh" within "b.sh".

In "a.sh" script, I have declared a variable, say "ndev=`lsdev -Cc tape`".

Can I show the output of "ndev" through "b.sh" script without declaring the same variable (ndev) in script "b.sh"?

Contents of a.sh:
****************
ndev=`lsdev -Cc tape`

Contents of b.sh:
*****************
sh a.sh
echo $ndev

Message was edited by: SGLFORUM
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Originally posted by: esv

in order to inherit variables defined in a.sh, you have to call it using the following syntax..

 . a.sh   ( dot a.sh)

best regards,
Enrique.
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