Originally posted by: CK_

I tried to obtain "runque" values from libperfstat.

I get two pattern of value, both are different from the value of vmstat.
How can I get the value equivalent to vmstat(r)?

 

1. perfstat_cpu_total_t:runque
It is very large as runque length. Also, the result increases monotonically.

runque = 4769829
runque = 4769832
runque = 4769837
.....

2. perfstat_cpu_t:runque 
It is output for each CPU.
The total value of runque is large than vmstat(r), as follows. 

name              = cpu0
runque            = 2

name              = cpu1
runque            = 0

name              = cpu2
runque            = 0

name              = cpu3
runque            = 0

name              = cpu4
runque            = 0

name              = cpu5
runque            = 0

name              = cpu6
runque            = 0

name              = cpu7
runque            = 0

$ vmstat 1 1

System Configuration: lcpu=8 mem=29824MB

kthr    memory              page              faults        cpu
----- ----------- ------------------------ ------------ -----------
 r  b   avm   fre  re  pi  po  fr   sr  cy  in   sy  cs us sy id wa
 0  0 877859 5321674   0   0   0   0    0   0   9 1252 619  0  0 99  0

Thank you for your cooperation.

 

#AIX-Forum

You need to take the difference over a period of time and then factor in the run occupancy.

Below two perfstat_cpu_total_t data structures called cpu_tot_p and cpu_tot_q   ->  the current (p) and previous values (q)

#define DELTA(member) (cpu_tot_p->member - cpu_tot_q->member)


if (DELTA(runque) == 0 || DELTA(runocc) == 0)
    pdouble("run_queue", 0.0);
else
    pdouble("run_queue", ((double)(DELTA(runque))) / ((double)(DELTA(runocc)))); /* fixed */

I am nosy, what are you actually up to with this cost?
Perhaps, I have suggestions that could help.
Cheers Nigel @mr_nmon

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Nigel Griffiths
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