WebSphere Application Server & Liberty

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Get node name of nodeagent server

  • 1.  Get node name of nodeagent server

    Posted Mon August 31, 2020 12:51 PM

    I have a code which can find all nodeagents and deployment manager servers.

    if scopetype == "nodeagent" or scopetype =="DeploymentManager": members = AdminTask.listServers('[-serverType '+scopename+']').splitlines() for member in members: print(member)

    result of this code is

    nodeagent(cells/somecell01/nodes/somenode01/servers/nodeagent|server.xml) nodeagent(cells/somecell01/nodes/somenode02/servers/nodeagent|server.xml) dmgr(cells/somecell01/nodes/somenode01/servers/dmgr|server.xml)

    Question is how can i get node name (somenode01,somenode02) of printed member?



    #Support
    #SupportMigration
    #WebSphereApplicationServer(WAS)


  • 2.  RE: Get node name of nodeagent server

    Posted Mon August 31, 2020 06:15 PM

    The easiest will be simple extraction from string like: member.split('/')[3]

    You can later confirm that this node exist by getting Node config

    members = AdminTask.listServers().splitlines() for member in members: print "ServerName: " + AdminConfig.showAttribute(member, 'name') nodeName = member.split('/')[3] print "Node name: " + nodeName node = AdminConfig.getid('/Node:'+nodeName+'/') print "Node name: " + AdminConfig.showAttribute(node,'name');



    #Support
    #SupportMigration
    #WebSphereApplicationServer(WAS)