Hi,

I only know this command to search logs for a particular string.

grep -n -i 'string'

Can someone please give me some useful commands to search application, systemout nodeagent logs affectively in day to day activities.

I searched everywhere but couldnt find any article describing effectively on commands

Thanks
Anil

grep -in

sed -n ',p'   |more


Example:
[root@HOSTNAME~]#grep -in  error SystemOut.log
18993:[9/4/13 8:11:17:570 GST] 00000020 ServerCache E DYNA1082E: WebSphere error1
19170:[9/4/13 8:11:17:570 GST] 00000020 ServerCache E DYNA1082E: WebSphere error1
[root@HOSTNAME~]#
[root@HOSTNAME~]#
[root@HOSTNAME~]#sed -n '18993, 19000p' SystemOut.log|more
 
Note:
The first command (grep)gives you the line numbers with patterns found in the file
In second command provide a start and end line number based on the output of the first command. ensure to put the letter "p" after the end line number.

You can either redirect it to a file using ">" redirective or through more command on the console.

Thanks
CB

Thank you siby for the reply..

But im using the grep -n -i '' and sed command as of now. Please let me know if there is any command to search between times and dates.

Ex- 9/4/13 8:11:17:570 to 9/4/13 8:20:17:570

Thanks in advance
Anil

You may try awk instead...

Example:

#awk '/10\/1\/13/{p=1} /10\/2\/13/{p=0}p' SystemOut.log |more

Here I have used "" as the delimiter. If your dates does not have symbols, you may try 

#awk '/01 Oct 2013/{p=1} /02 Oct 2013/{p=0} p'  SystemOut.log |more


Thanks
CB