Looks like you've posted a snippet of Python code using the Cplex library, likely for solving an optimization problem. It seems to be a linear programming problem given the use of linear constraints and an objective function with a sense of maximization.
Here's a breakdown of the code:
1.Objective Function:
2.my_obj: Represents the coefficients of the objective function.
3.my_prob.objective.set_sense(my_prob.objective.sense.maximize): Sets the optimization sense to maximize.
4.Variables:
5.my_ub: Represents the upper bounds of the variables.
6.my_colnames: Names of the variables.
7.Linear Constraints:
8.rows: Represents the coefficients and structure of the linear constraints.
9.my_sense: Specifies the sense of each constraint (E for equality, L for less than or equal to).
10.my_rhs: Right-hand side values of the constraints.
11.my_rownames: Names of the constraints.
12.Cplex Problem Initialization:
13.my_prob: Initializes the Cplex optimization problem.
14.Adds the objective function, variables, and linear constraints.
15.Solution:
16.my_prob.solve(): Solves the optimization problem.
17.Error Handling:
18.The code includes a try-except block to catch and print any CplexError that might occur during the solution process.
Note: The code contains placeholders like p, prod, v, C which are not defined in the provided snippet. Make sure to define these variables with appropriate values before running the code. Additionally, the return statement at the end might need to be within a function.
If you have specific questions about parts of the code or if you encounter any issues, feel free to ask!
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子豪 张
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Original Message:
Sent: Wed December 21, 2022 12:31 AM
From: oscar clark
Subject: already installed cplex and import cplexerror but still have syntax error
I'm encountering an error in the following lines:
import cplex from cplex.exceptions import CplexError def capAst_LP(prod, C, p, v, meta = None):
# st = time.time() try: my_prob = cplex.Cplex() my_obj = list(p) #including the 0th coordinate my_ub = [cplex.infinity for i in p] #omitting lb as 0 my_colnames = ['z_'+str(i) for i in range(prod+1)] my_rhs = [1]+[0 for i in range(prod+1)] my_rownames = ['sum2one','capaciy'] + ['lpr_'+str(i+1) for i in range(prod)] my_sense = ''.join(['E']+['L' for i in range(prod+1)]) # print my_obj # print my_ub # print my_colnames # print my_rhs # print my_rownames # print my_sense my_prob.objective.set_sense(my_prob.objective.sense.maximize) my_prob.variables.add(obj = my_obj, ub = my_ub, names = my_colnames) # print my_prob.variables.get_lower_bounds() # print my_prob.variables.get_upper_bounds() # print my_prob.variables.get_names() rows = [] rows.append([range(prod+1),[1 for i in range(prod+1)]]) vcoeff_vec = [-C] for i in range(1,prod+1): vcoeff_vec.append(round(v[0]*1.0/v[i],7)) rows.append([range(prod+1),vcoeff_vec]) for i in range(1,prod+1): inequ_vec = [-v[i]] for j in range(1,prod+1): if j==i: inequ_vec.append(v[0]) else: inequ_vec.append(0) rows.append([range(prod+1),inequ_vec]) # print rows my_prob.linear_constraints.add(lin_expr = rows, senses = my_sense, rhs = my_rhs, names = my_rownames) my_prob.set_log_stream(None) my_prob.set_error_stream(None) my_prob.set_warning_stream(None) my_prob.set_results_stream(None) st = time.time() my_prob.solve()except CplexError, exc: print exc return
except CplexError, exc: print exc return
I have installed cplex and I'm using python 3.7. I will iterate the codes.
File "", line 304 except cplexError, exc: ^ SyntaxError: invalid syntax
Thanks,
jesonzale
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oscar clark
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