I'm encountering an error in the following lines:
import cplex from cplex.exceptions import CplexError def capAst_LP(prod, C, p, v, meta = None):
# st = time.time()
try:
my_prob = cplex.Cplex()
my_obj = list(p) #including the 0th coordinate
my_ub = [cplex.infinity for i in p] #omitting lb as 0
my_colnames = ['z_'+str(i) for i in range(prod+1)]
my_rhs = [1]+[0 for i in range(prod+1)]
my_rownames = ['sum2one','capaciy'] + ['lpr_'+str(i+1) for i in range(prod)]
my_sense = ''.join(['E']+['L' for i in range(prod+1)])
# print my_obj
# print my_ub
# print my_colnames
# print my_rhs
# print my_rownames
# print my_sense
my_prob.objective.set_sense(my_prob.objective.sense.maximize)
my_prob.variables.add(obj = my_obj, ub = my_ub, names = my_colnames)
# print my_prob.variables.get_lower_bounds()
# print my_prob.variables.get_upper_bounds()
# print my_prob.variables.get_names()
rows = []
rows.append([range(prod+1),[1 for i in range(prod+1)]])
vcoeff_vec = [-C]
for i in range(1,prod+1):
vcoeff_vec.append(round(v[0]*1.0/v[i],7))
rows.append([range(prod+1),vcoeff_vec])
for i in range(1,prod+1):
inequ_vec = [-v[i]]
for j in range(1,prod+1):
if j==i:
inequ_vec.append(v[0])
else:
inequ_vec.append(0)
rows.append([range(prod+1),inequ_vec])
# print rows
my_prob.linear_constraints.add(lin_expr = rows,
senses = my_sense,
rhs = my_rhs,
names = my_rownames)
my_prob.set_log_stream(None)
my_prob.set_error_stream(None)
my_prob.set_warning_stream(None)
my_prob.set_results_stream(None)
st = time.time()
my_prob.solve()
except CplexError, exc:
print exc
return
except CplexError, exc: print exc return
I have installed cplex and I'm using python 3.7. I will iterate the codes.
File "", line 304 except cplexError, exc: ^ SyntaxError: invalid syntax
Thanks,
jesonzale
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oscar clark
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