I am not familiar with the Rao-Scott Chi-square. But I think someone should point out that the various rules of thumb for Pearson Chi-square tests propose minimum expected counts, not observed counts.
One common rule of thumb for Pearson's Chi-square says all cells must have expected counts of at least 5. But IMO, this is not the best rule of thumb. For 2x2 tables, I recommend this advice from Ian Campbell. And for tables larger than 2x2, I recommend the advice from Yates, Moore & McCabe (1999, p. 734). They say that the Chi-square approximation is good enough if "[n]o more than 20% of the expected counts are less than 5 and all individual expected counts are 1 or greater".
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Bruce Weaver
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Original Message:
Sent: Thu April 10, 2025 08:20 PM
From: Love Ara
Subject: Rao-Scott chi-square when a cell is = 0
What if in the contingency table when calculated there is a cell whose expected frequency is less than 5 for the 2*2 and 2*3 tables, can we still use the Pearson chi square from the Rao-Scott chi square results?
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Love Ara
Original Message:
Sent: Tue December 05, 2023 04:42 PM
From: Augusto Norte
Subject: Rao-Scott chi-square when a cell is = 0
We are conducting a study in which we analyze data from a survey whith a complex sampling design. Therefore, to determine if there is an association or independence between categorical variables, we use the Rao-Scott chi-square provided by the complex samples module of SPSS.
As we understand, the Rao-Scott chi-square statistic cannot be calculated when there is a cell with a frequency equal to zero (https://www.ncbi.nlm.nih.gov/pmc/articles/PMC4567525/). And we have some contingency tables in which this case occurs and yet SPSS calculates a statistic and its associated p-value.
Would kindly inform us how is it possible for SPSS to calculate it? What adjustments are made to the calculation formula? What assumptions does it make?
Thanks in advance,
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Augusto Norte
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