Originally posted by: xspeng

There are three goals in my model,I want to solve  the first goal, and use the values of these decision variables to get the value of the other two target functions at this time,But I don't know how todo that.

Hi,

could

https://www.ibm.com/developerworks/community/forums/html/topic?id=193ecefc-757c-4c66-9905-7ac0dd81dc8f&ps=25

help you to start ?

regards

Originally posted by: xspeng

I've already used staticLex  function and set a time limit, But no solution can be obtained in time limit, I have reattached my.model and .data

Hi,

CPLEX would work better than CPO for this so I would rather use CPLEX

but then indeed you do not have staticLex but

minimize //staticLex(
 TOTAL_COST
 //, ENVIM,-SCIM)
 ;

so from there you could use the flow control scripting (choice 2)  I suggested at

https://www.ibm.com/developerworks/community/forums/html/topic?id=193ecefc-757c-4c66-9905-7ac0dd81dc8f&ps=25

regards

Originally posted by: xspeng

i have used the flow control scripting (choice 2)  you suggested at
https://www.ibm.com/developerworks/community/forums/html/topic?id=193ecefc-757c-4c66-9905-7ac0dd81dc8f&ps=25

but it can't work, because your objectives are var ,my objectives are expr, I have no idea how to deal with this problem, please help me.

Hi,

what you could do is add decision variables that would be equal to the decision expressions:

 int n=10;
int m=25;

range position = 1..n;
    dvar boolean x[position][position];
    dexpr int obj1=max(i,j in position) i*x[i][j];
    dexpr  int obj2=max(i,j in position) j*x[i][j];
    
    dvar int vobj1;
    dvar int vobj2;

    minimize (vobj1-1)*n+vobj2;

    subject to
    {
      sum(i,j in position) x[i][j]==m;
      vobj1==obj1;
      vobj2==obj2;
     
      //obj1==max(i,j in position) i*x[i][j];
      //obj2==max(i,j in position) j*x[i][j];
    }

    execute
    {
    writeln("objectives : ",obj1," ",obj2);

    writeln("-----------------------------");
    writeln();

    for(var i in position)
    {
     for(j in position) write((x[i][j]==1)?"+":" ");
     writeln();
    }
    }

     main
     {
       thisOplModel.generate();
       cplex.setObjCoef(thisOplModel.vobj2,0);
       cplex.solve();
       thisOplModel.postProcess();
       var obj1=thisOplModel.obj1.solutionValue;
       thisOplModel.vobj1.LB=obj1;
       thisOplModel.vobj1.UB=obj1;
       cplex.setObjCoef(thisOplModel.vobj2,1);
       cplex.solve();
       thisOplModel.postProcess();
        
     }

regards

Originally posted by: xspeng

 There are three goals in my model,i use flow control to solve with the first objective:TOTAL_COST, then the second objective: ENVIM  while freezing the first one, and finally the third : SCIM  while freezing the first one and second one. But the results were incorrect, I don't know am i coding  right or wrong, would you examine these for me, please?

My control flow code as follow:

main
 {
   thisOplModel.generate();
   cplex.setObjCoef(thisOplModel.vSCIM,0);
   cplex.solve();
   thisOplModel.postProcess();
   var ENVIM=thisOplModel.ENVIM.solutionValue;
   thisOplModel.vENVIM.LB=ENVIM;
   thisOplModel.vENVIM.UB=ENVIM;
   cplex.setObjCoef(thisOplModel.vSCIM,1);
   cplex.solve();
   thisOplModel.postProcess();
   cplex.setObjCoef(thisOplModel.vENVIM,0);
   cplex.solve();
   thisOplModel.postProcess();
   var TOTAL_COST=thisOplModel.TOTAL_COST.solutionValue;
   thisOplModel.vTOTAL_COST.LB=TOTAL_COST;
   thisOplModel.vTOTAL_COST.UB=TOTAL_COST;
   cplex.setObjCoef(thisOplModel.vENVIM,1);
   cplex.solve();
   thisOplModel.postProcess(); 
 }

Hi,

since your objective is

minimize TOTAL_COST + ENVIM - SCIM;

in the main

cplex.setObjCoef(thisOplModel.vSCIM,1);

should be

cplex.setObjCoef(thisOplModel.vSCIM,-1);

regards

Originally posted by: xspeng

I have changed it as you suggest.But the representative optimal result  of TOTAL_COST  is different from the individual optimization  result  of TOTAL_COST,I don't know am i coding  right or wrong, would you examine these for me, please?

My control flow code as follow:

main
 {
   thisOplModel.generate();
   cplex.setObjCoef(thisOplModel.vSCIM,0);
   cplex.solve();
   thisOplModel.postProcess();
   var ENVIM=thisOplModel.ENVIM.solutionValue;
   thisOplModel.vENVIM.LB=ENVIM;
   thisOplModel.vENVIM.UB=ENVIM;
   cplex.setObjCoef(thisOplModel.vSCIM,-1);
   cplex.solve();
   thisOplModel.postProcess();
   thisOplModel.generate();
   cplex.setObjCoef(thisOplModel.vENVIM,0);
   cplex.solve();
   thisOplModel.postProcess();
   var TOTAL_COST=thisOplModel.TOTAL_COST.solutionValue;
   thisOplModel.vTOTAL_COST.LB=TOTAL_COST;
   thisOplModel.vTOTAL_COST.UB=TOTAL_COST;
   cplex.setObjCoef(thisOplModel.vENVIM,1);
   cplex.solve();
   thisOplModel.postProcess(); 
 }

Hi,

I see

 thisOplModel.generate();
   cplex.setObjCoef(thisOplModel.vSCIM,0);
   cplex.solve();

but since you have 3 KPIs, you should also set a second coef to 0

regards

Originally posted by: xspeng

I don't know how to set a second coef to 0,I hope that you can help me, Thank You.

Hi

you could turn

 thisOplModel.generate();
   cplex.setObjCoef(thisOplModel.vSCIM,0);
   cplex.solve();

into

 thisOplModel.generate();
   cplex.setObjCoef(thisOplModel.vSCIM,0);

   cplex.setObjCoef(thisOplModel.vENVIM,0);
   cplex.solve();

regards