Originally posted by: SystemAdmin

I tested the command it works on command line, but within script it return nothing. I changed the quotation, but no result. Can someone please take a look and let me know.

[b]textfile="$(ls -al "$directory1" | awk '{print $10}' | grep -v "^ *$" | sort |
grep -v "./")"[b]
#text_file="$(ls -al "$directory1" | awk '{print $10}')"
#textFile=`cat out1.txt`
echo "$textfile"
cat out1.txt | while read line
#for line in "$teixtfile"
do
echo "$line"
find $directory2 -type f -name "$line"
if $? -eq 0
then
diff "$directory1$line" "$directory2$line" > logdiff.out
case $? in
0) let "count_same +=1";;
1) let "count_diff +=1";;
2) echo 'exit 2' >&2;;
*) echo 'some other exit' $? >&2;;
esac

fi
done

Originally posted by: nagger

There are lots of bugs in here.
1) textfile spelt teixfile
2) You assign textfile and then cat out1.txt
3) my ls -al only has 9 columns so awk print $10 returns nothing
4) You have commented out stuff - I guess you are trying to debug it
5) What is the point of echoing 'exit 2' ?
6) $directory2 is used but not set
7) $line is set in a commented out line
8) the counts are not output at the end
and more ...

What are you trying to do?
I can't help thinking it must be easier to start again.

If you are trying to compare two directories ...
How about: diff -h -b Dir1 Dir2