Hi Jon, I understand. Does this mean I would still need to compare all of the others against one another?
Do I report the table just like this? I just want to make sure I am not missing reporting information that is needed.
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Stacy Adams
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Original Message:
Sent: Thu June 01, 2023 07:52 PM
From: Jon Peck
Subject: Linear Mixed Models - Redundancy
The contrasts are comparisons against Treatment 4. If there were no other variables, that would leave the intercept value (assuming that you are using treatment contrasts, which is the default).
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Original Message:
Sent: 6/1/2023 7:02:00 PM
From: Stacy Adams
Subject: Linear Mixed Models - Redundancy
Hello, I am running some linear mixed models with categorial variables. The last line of each one is always set to redundant. For example:
Intercept | 94.458 | 14.626 | 144.296 | 6.458 | <.001 | 65.549 | 123.367 |
Treatment 1 | 36.177 | 9.928 | 338.236 | 3.644 | <.001 | 16.649 | 55.704 |
Treatment 2 | 9.553 | 9.919 | 338.079 | .963 | .336 | -9.959 | 29.064 |
Treatment 3 | 12.878 | 9.680 | 337.363 | 1.330 | .184 | -6.162 | 31.918 |
Treatment 4 | 0b | 0 | | | | . | . |
My question is, how can I obtain the values for the last variable?
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Stacy Adams
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